Traditional Culture Encyclopedia - Hotel accommodation - Hotel air source
Hotel air source
Q = (55-8) x10x1000x1kcal/kg = 470,000 kcal; If the energy efficiency ratio of the heat pump is 2 at this temperature (it can reach 4 in summer and much lower in winter), the heat pump does work w = q/2 = 235000 kcal. If water is boiled every day, the required heat pump power is p = 235,000/10 = 23,500 kcal/h, then p = 23,500 x1.163/1000 = 27.3 kw (about 37 horses). Of course, if it is not too cold at night, you can also use a heat pump (for example, one day 15 hours), so the installed power can be smaller. You can use the above formula to calculate the weather.
There are many ways for hotels to save energy, such as heat recovery in restaurants and guest rooms, the use of solar hot water and so on.
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