Xi 'an Chanba H Hotel

(1) From the image, the BC section is more inclined than the AB section, so it is the BC section that rides the bike.

(2) The distance of section AB is sAB= 1800m, and the time tAB=25min= 1500s.

The distance of BC section SBC = 3600 m-1800 m =1800 m, the time tBC=30min-25min=5min=300s,

Xiaoming's walking speed VAB = sabtab =1800m1500s =1.2m/s;

Circulating speed VBC = SBCTBC =1800m300s = 6m/s. 。

(3) The whole journey s=3600m, the time t=30min= 1800s,

The average speed of the whole process is V = ST = 3600 m1800 s = 2 m/s = 7.2 km/h. 。

Answer: (1) The picture of the distance and time of Xiaoming's cycling is the BC segment in the picture;

(2) Xiaoming's walking speed is1.2m/s; Xiaoming's riding speed is 6m/s;

(3) Xiaoming's average speed from home to Xi 'an Ba National Wetland Park is 7.2 km/h. 。