Wenzhou L2 photography

(1) The speed of BC section is V, and the time of passing through AB is t 1.

Then in section AB: xab =12vt1= l1?

In BC segment: L2=Vt2?

t 1+t2=t？

So: V=L2+2L 1t

(2) The acceleration of uniformly accelerated linear motion in section 2)AB: a=V22L 1.

So: a=(L2+2L 1)22L 1t2.

Answer: (1) The speed of the BC helicopter is L2+2l1t;

(2) When doing uniform acceleration linear motion in section AB, the acceleration is (L2+2L 1) 22L 1t2.