3v wedding photography beach

Meter barrel+meter seawater =12.27kg (2)

Rice barrel+rice seawater-misha =10.27kg (3)

M barrel +m tap water = 1 1.27kg (4)

(2)-(3)

Rice sand = 2 kg

(4)-( 1)

M tap water =10.27kg.

V volume =m tap water/ρ water =10.27/1=10.27dm3 (ρ water = 1 kg/DM 3).

(3)-( 1)

M remaining seawater = 9.27kg

V residual seawater =m residual seawater/ρ seawater = 9.27/ 1.03 = 9 DM 3.

V sand =V volume -V residual water = 10.27-9 = 1.27 DM 3.

ρ sand =m sand /V sand = 2/1.27 =1.57kg/dm 3 =1.57 *103/m 3 (the result of the first question).

Sediment concentration m

Cubic meter/1000 cubic decimeter = cubic meter of sand/cubic meter of capacity (1 cubic decimeter = 1000 cubic decimeter)

m = 1000 * 2/ 10.27 = 194.7kg