Who can help me solve two primary school math problems? Answer quickly!

1. Solution: Let this pile of bricks have x blocks.

( 1- 1/4)x+306 =( 1+ 1/5)x

x=680

2. Solution: Let four numbers be AX, BX, CX and DX, where X is their greatest common factor.

According to the question, ax+bx+cx+dx=370.

To maximize x, (a+b+c+d) must be the smallest integer divisible by 370.

So a+b+c+d= 10.

a= 1

b=2

c=3

d=4

The four numbers are 37.

74

1 1 1

148