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Known: m=9.27× 105kg? ρ seawater =1.03x103kg/m3? g= 10N/kg？ H = 300m m

Q: (1)V row =? (2)p=？

Solution:

(1) The submarine is floating on the sea.

F floating =G

Row m =m

∑ρ= mV

∴ The volume of seawater discharged by submarine is V row =m row ρ seawater =mρ seawater = 9.27×105 kg1.03×103 kg/m3 = 900 m3.

(2) The pressure of seawater on the seabed is p=ρ seawater GH =1.03x103kg/m3×10? N/kg×300m=3.09× 106Pa。

Answer: (1) The amount of seawater discharged by submarine is 900m3. ..

(2) The seabed pressure is 3.09× 106Pa. Dad.