Traditional Culture Encyclopedia - Photography and portraiture - Knowing the asymptote and a point, how to solve hyperbolic equation, method and process. Question six, question one

Knowing the asymptote and a point, how to solve hyperbolic equation, method and process. Question six, question one

The asymptote is x/3+y/4=0.

So the hyperbolic equation can be set to x? /9 -y? / 16=λ,

Substituting (15/4,3) gives λ = 25/16-9/16 =1.

That is, the equation of hyperbola is x? /9 -y? / 16= 1