During the holiday, the school organized 360 teachers and students to travel abroad. A bus rental company has two kinds of buses to choose from: 40 Class A buses with a rent of 400.

If you only rent an A-class bus, you need 360÷40=9. If you only rent a B-class bus, you need 8 buses, but one of them can't be full. If you only rent an A-class bus, it must be the most expensive way. Therefore, eight buses are rented by * * *. Both buses carry more than 360 passengers. According to this inequality, we can find out the respective numbers of two buses and then calculate the rent.

Solution: It takes 360÷40=9 vehicles to rent only Class A buses. It takes 8 cars to rent only Class B buses, so both types of buses rent 8 cars.

If there are x cars in A and 8-x cars in B, then 40x+50(8-x)≥360.

Solution: x≤4

Integer solutions are 1, 2, 3, 4.

Rent a car W=400x+480(8-x), that is, W=-80x+3840.

The value of w decreases with the increase of x, so when x=4, w is the smallest.

So, let x=4, and the minimum value of w is 3520 yuan.