Since 20 12, smog has ravaged my hometown Handan for countless times. Among them, coal burning and automobile exhaust are one of the causes of air pollution. (1) Automobile exhaust

(2)CH 4 (g) +N 2 O 4 (g) =N 2 (g) +2H 2 O (g)+CO 2 (g) △ H =-898.1KJ/mol.

(3)①CH4—8e—+2H 2o = CO2+8H+② 14？ ③1.68L.

Test and analysis: (1)① Write [CO 2] 2 [N 2]/[NO] 2 [CO] 2: The product of the quadratic power of the product equilibrium concentration coefficient is greater than the product of the quadratic power of the reactant equilibrium concentration coefficient; ② A. After the reversible reaction reaches equilibrium, the positive and negative rates are equal and will not change. According to the image, V is the largest at t 1, which changes with the reaction rate and does not reach equilibrium, which is wrong. B, positive and negative reactions should be exothermic, with the increase of reaction temperature, the chemical equilibrium constant decreases, and after reaching equilibrium, the temperature remains unchanged, the equilibrium constant remains unchanged, and the image is consistent with the actual situation and correct; After c and t 1, the amount of carbon dioxide and NO changes, and t 1 does not reach an equilibrium state, which is an error; D, with the progress of the reaction, the mass fraction of NO decreases gradually, and the mass fraction of NO remains unchanged at t 1, which is in an equilibrium state and correct; Answer BD;

(2) It is known that I CH4 (g)+2NO2 (g) = N2 (g)+CO2 (g)+2H2O (g) △ H =-867 kJ/mol Ⅱ 2NO2 (g) N2O4 (g)? △H=-56.9 kJ/mol？ ⅲH2O(g)= H2O(l)？ Δ h =-44.0kJ/mol. According to Goose's law, I-II+III× 2 gives CH4 (g)+N2O4 (g) = N2 (g)+2H2O (g)+CO2 (g) △ h =-898.1kj/mol.

(3)① Methane in methane fuel cell generates CO2- and H 2 O under the acidic condition of cathodic oxidation reaction. The negative reaction formula is CH 4-8e-+H 2O = CO 2+8h+. ② According to the meaning of the question, n(NaCl)=0. 1mol. The electrolysis process is to electrolyze saturated brine first and then electrolyze water. According to the electrolytic equations 2cl-+2H2, H 2 ↑+Cl 2 ↑+2OH-, substituting the data to calculate that n(OH-)=0. 1mol, the concentration is 1mol/L, and the pH of the electrolytic solution is14; ③n(NaCl)=0. 1mol, and the amount of chlorine gas produced by electrolysis is 0.05mol. According to the meaning of the question, the electrolysis process is to electrolyze saturated brine first, then electrolyze water, and the electrode reaction formula is 2H++2e-=H 2 ↑? 2Cl - - 2e - =Cl 2 ↑？ 4oh-4e-= O2 = 2h2o, and the hydrogen production of cathode is 0. 1mol. According to the conservation of electrons, 2n(H 2 )=2n(Cl-)+4n(O 2) is substituted into the data, and it is calculated that n(O 2 )=0.075mol, and the anode * * * generates 0.