In recent years, smog weather has ravaged parts of China many times. Coal burning and automobile exhaust are one of the causes of air pollution. (1) automobile exhaust purification.

(1)① As can be seen from the figure 1, the temperature T 1 reaches equilibrium first, so the temperature T 1 >T 2. The higher the temperature, the lower the concentration of carbon dioxide, indicating that the temperature balance moves to the reverse reaction, so the positive and negative reactions should be exothermic, that is, △ h < 0, so the answer is:

(2) As can be seen from the figure, 2s reaches equilibrium at T 2 temperature, and the change of carbon dioxide concentration at equilibrium is 0. 1mol/L, so V (CO2) = 0.1mol/L2S = 0.05 mol/(L? S), the rate ratio is equal to the stoichiometric ratio, so v (N2) =1.2v (CO2) =1.2× 0.05mol/(l? s)=0.025mol/(L？ s)，

So the answer is: 0.025mol/(L? s)；

③ A. After reaching the equilibrium, the forward and backward rates are equal and will not change. When t 1, v is the largest, and then changes with the reaction rate, and does not reach equilibrium, so a is wrong;

After b, t 1, the amounts of carbon dioxide and NO changed, and t 1 did not reach an equilibrium state, so b was wrong;

The mass fractions of C and NO remain unchanged, and t 1 is always in equilibrium, so C is correct.

So, the answer is: c;

(2) It is known: ① CH4 (g)+2NO2 (g) ═ N2 (g)+CO2 (g)+2H2O (g) △ h1=-867 kJ/mol 22NO2 (g)? Nitrous oxide (g) △ hydrogen =-56.9 kJ/mol

③H 2 O(g)=H 2 O(l)△H=-44.0kJ？ Mol-1

According to Gaith's law, 1-2+3× 2 is CH4 (g)+N2O4 (g) = N2 (g)+CO2 (g)+2h2o (l).

So △ h =-867kj/mol-(-56.9kj/mol)-44.0kj? mol- 1×2 =-898. 1kJ/mol，

Namely CH4 (g)+N2O4 (g) = N2 (g)+CO2 (g)+2h2o (l), △H=-898. 1kJ/mol,

So the answer is: CH4 (g)+N2O4 (g) ═ N2 (g)+CO2 (g)+2h2o (L) △ H ═-898.1kj/mol;

(3)① The anode of the primary battery undergoes oxidation reaction, and methane is introduced into the anode. Under acidic conditions, oxidation reaction occurs to generate CO 2 and H+, and the reaction formula of anode electrode is: CH 4 -8e-+2H 2 O=CO 2 +8H+.

Therefore, the answer is: ch 4-8e-+2h2o = co 2+8h+;

② The equation of electrifying: 2 NaCl+2 H2O.2 2NaOH+H 2 ↑+Cl 2 ↑ ↑ Cl 2 ↑.

2 2 22.4

0. 1l× 1mol/l 0. 1 2.24 l

According to the title, the reaction is to electrolyze water directly, and the pH value of the solution remains unchanged, C (H+) =10-140.10 = 14, so the pH value =/kloc-0.

So the answer is14;

(3) methane fuel cell electrolysis 100mL 1mol/L salt solution, where n(Cl-)=0. 1mol. After electrolysis for a period of time, 2.24L of hydrogen was collected under standard conditions, and the amount of substance was 0. 1mol. According to the analysis of electrolytic reaction and electron conservation, the cathode is 2h++2e. Anode electrode reaction: 2cl-2e-= Cl2 ↑, 0. 1mol chloride ion loses electrons 0. 1mol to generate chlorine gas 0.025mol, so hydroxide ion loses electrons 0. 1mol, 4oh-4e-= 2h2o+O2 ↑, and transfers electrons 0./. * * * The amount of gas substance generated =0.05mol+0.025mol=0.075mol, and the volume of standard gas = 0.075mol× 22.4l/mol =1.68l,

The answer is: 1.68.