Traditional Culture Encyclopedia - Photography major - Odd-even contrast photography
Odd-even contrast photography
Suppose there are x people in the last row, a total of n rows, then start from the back.
The number of people in the front row is x, kx+ 1, x+2, …, x+
(n- 1).
Because x and n are positive integers and n≥3, n
(n- 1), and the parity of n is different from 2k+(n- 1).
Decomposition of 200 into prime factors indicates that n=5 or n=8. When n=5,
k = 18; When n=8, k=9. There are two different schemes.
2. The formula is (98 ÷ 2-1)+(98 ÷ 4-1) = 71(
answer
First, we know that A and B are positive integers.
Answer? -B? =(a+b)(a-b), and (a+b)(a-b) is an odd number.
Even parity is the same, that is, even or odd. And 2
One big and one small.
(1) If both are odd numbers, then 1 must be excluded because it is odd.
Multiplying this number by 1 is surprising in itself. Then everything else fits.
Among the 98 odd-even cycle numbers, the odd number is 98÷2=49.
(piece), excluding 1, 49- 1=48 (piece)
(2) Both are even numbers, that is, k is even number, and it is two even numbers.
The products are even numbers, so the minimum requirement is that k is a multiple of 4.
But it must be a multiple of 4, 98÷4=24 (pieces) but divided by 4.
The factor of 1 can only be divided by 2×2, which means it cannot be combined.
Same, so 24- 1=23 (pieces)
48+23=7 1 (pieces)
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