At a wedding, the photographer arranged for six people to take pictures in succession, including the bride and Sina. How many permutations are there if the following conditions are met?

First of all, the permutation and combination of all six people in a random row is 6*5*4*3*2* 1=720.

The bride must be next to the groom: we package the bride and groom into one person (whole), which is equivalent to five people. There are 5*4*3*2* 1= 120 combinations, but note that although the bride and groom are packaged as one person, there are two possibilities, the bride is on the groom's left or the bride is on the groom's right, so,

The groom is not next to the bride: six people are randomly arranged, and the bride must be next to the groom, which means that the groom is not next to the bride, 720-240=480.

The bride's position on the groom's left: referring to the first question, there are no two possibilities, so it is 5*4*3*2* 1= 120.