(2009? Yantai) Tengfei Middle School has built eight new "Tengfei" sculptures in front of the teaching building (left). To measure the height of these sculptures, Ming found them on the second floor.

Solution: intersection c is CE⊥ 5, and intersection b is e.

∠∠ Five DC = 90- 10 = 30, ∠ Five CD = 90-30 = 10,

∴∠C Five d = 90.

CD = n0，

Five C=n, CD = 9.

In Rt△5 CE,

∵∠∠∠∠∠∠∠∠∠∠∠∠∠∠∠∠∠∠∠∠∠∠∠∠∠∠∠∠873

∴ five E=n, five C= nine,

CE =？ Cos∠ five CE= nine? Cos30 = nine to three.

In Rt△BCE,

∫∠BCE = 4 Nine,

∴BE=CE= nine to three,

∴ five B= five E+BE= nine+nine 3 = nine (3+n)≈ 10.8 (m).

Therefore, the height of sculpture V B is about10.8m..