Photographers need to take pictures of five students and two teachers in a row. How many different arrangements are there between two teachers? Anxious to kneel down to the master.

Because the two teachers are not at both ends, there is a student at each end. Choose two rows from five students at both ends. Just C52 times 2=20 (I wonder if you understand? C is a letter, 5 is on the lower right of C, and 2 is on the upper right of C (this is the formula).

There are three students and two teachers left, because the two teachers are adjacent, so we can regard the two teachers as one (there are two situations: one teacher is on the right and the other teacher is on the left; In this way, the three students and two teachers tied together are randomly arranged among the two students, that is, A44 times 2=48 (as above, the letters A, 4 are at the lower right and 4 are at the upper right).

Multiply two numbers by 20*48=960.

So there are 960 ways.