Shenzhen rt photography activities

Solution: As shown in the figure, the intersection point D is DE⊥AB in E,

∫∠C = 90，AC=6，BC=8，

∴AB=AC2+BC2=62+82= 10，

∫AD splitting∠ ∠CAB,

∴CD=DE，

∴S△ABC= 12AC？ CD+ 12AB？ DE= 12AC？ BC,

That is 12×6? CD+ 12× 10？ CD= 12×6×8，

Solution CD = 3.

So the answer is: 3.