Traditional Culture Encyclopedia - Photography and portraiture - Given the directional quantities A = (- 1, 2,3) and B = (1, 1, 1), what is the injectivity of vector a in the direction B?
Given the directional quantities A = (- 1, 2,3) and B = (1, 1, 1), what is the injectivity of vector a in the direction B?
cos(a，b)=a*b/|a|*|b|
=(- 1* 1+2* 1+3* 1)/(√( 1^2+2^2+3^2)*√( 1^2+ 1^2+ 1^2)
=√3/3
therefore
The injectivity of vector A in direction B is | a | cos (a, b) = √ (1 2+2 2+3 2) * √ 3/3.
=4√3/3
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