Photographer Xiao Jiang

Solution: (1) According to the law of conservation of mass, the mass of CO2 released by the reaction = (100.0g+14.0g)-108.5g = 5.5g;

(2) Let the mass of CaCO3 in 12.0g limestone sample be x.

CaCO3+2HCl═CaCl2+CO2↑+H2O

100

Forty-four

x？ 5.5g

Equation: 100/x=44/5.5. The solution is: x =12.5g.

Therefore, the purity of this limestone sample is12.5/14×100% = 89.29%.

Because 89.29% > 85%, the purity of limestone samples meets the requirements.

Answer: (1) The mass of carbon dioxide produced in this experiment is 5.5g；; (2) The purity of limestone samples meets the requirements.

Satisfied, please adopt!