Mathematics in Tourism

Composition topic: Mathematics in Tourism

Keywords: Mathematics Tourism Primary School Grade One

This article applies to: the first grade of primary school.

Composition source:

This composition is about 500 words in the first grade of primary school, and the topic is "Mathematics in Tourism". Everyone is welcome to contribute.

Mathematics in Tourism

Xingfu ST primary school San Wu ban Zhang

Fireworks are set off in Yangzhou in March, and it is a good time to travel in bloom in spring. The teacher is going to take the whole class to Shennong Mountain for an outing to see peach blossoms. Bring your own lunch, fare AA system. At present, there are two types of travel companies. Each passenger car 120 yuan, carrying capacity 12 people. Each bus 160 yuan, limited load 18 passengers. There are 40 people in the class. How to rent a car is the most economical way?

I raised my hand and replied, "Rent two cars, one big car is the most suitable, and 400 yuan is enough." "Zhang, how do you calculate? Tell us about it. " Teacher Xing said.

I went on to say, "If you want to rent the cheapest car, you must meet the following two points: (1) All the seats in the rented car are full, even if there are not enough seats, the less empty the better.

(2) Rented cars cost the least per capita.

As Wang Haoyu said, renting a big car costs less per capita, so renting a big car is cheaper than renting a small car. So rent a big car first, and then gradually increase the number of cars according to the fewer seats.

Rent a car (1). All 40 people get on the bus. If you rent three cars, there is still 18× 3-40 = 14 (seats), and the rent is 160×3=480 (yuan).

(2) All 40 people get on the bus. If you rent two buses and one minibus, there is 2× 18+ 12-40 = 8 (seats) left, and the rent is 160×2+ 120=440 (yuan).

(3) All 40 people get on the bus. If 1 bus and 2 passenger cars are rented, there is still 18+ 12× 2-40 = 2 (seats), and the rent is 160+ 120×2=400.

(4) All 40 people get on the bus. If four minibuses are rented, there is still 12× 4-40 = 8 (seats), and the rent is 120×4=480 (yuan).

By comparing the above four schemes, we can find that the third scheme is the most economical. "

Number of buses, number of minibuses, number of seats, rent/yuan Scheme I 3 0 54 480 Scheme II 2 1 48 440 Scheme III 1 2 42 400 Scheme IV 0 4 48 480

From the above table, we can see more clearly that the third scheme has the least empty seats and the least cost shared by each student. "Students, we rent a car according to Zhang's plan, prepare snacks after school on Friday afternoon, and meet at the school gate on Saturday morning." Teacher Xing said.

After class, the students are talking about it. This math is really important! If we choose the wrong plan, we will have to spend more money in 80 yuan. Zhang is really a "little mathematician" in our class. I don't want to laugh at my classmates' praise.

(20 13 March 17)