Yang Yang and Guang Guang play poker, and four cards of the same size and texture are marked as Travel 1, 2, 3, 4.

Solution: The list of solutions 1 is as follows (tree diagram).

1 2 3 4

2 3 4 1 3 4 1 2 4 1 2 3

Results (12) (13) (14)

(2 1)(23)(24)

(3 1)(32)(34)

(4 1)(42)(43)

Event * * * has 12 results.

And that possibility of each result is the same.

Among them, Yang Yang won six kinds.

Yang Yang won = half.

Scheme 2 is as follows (tree diagram)

1 2 3 4

1234 1234 1234 1234

Results (12) (13) (14) (11)

(2 1)(23)(24)(22)

(3 1)(32)(34)(33)

(4 1)(42)(43)(44)

Event * * * has 16 results.

And that possibility of each result is the same.

Among them, Yangyang wins seven kinds.

Yang Yang won =/kloc-7 out of 0/6.

Because 1 Table P Yang Yang won more than Table 2 P Yang Yang won.

So plan one is good for Yang Yang.