The tourist route of a scenic spot is shown in figure 1, where A is the entrance, B, C and D are the scenic spots, and E is the fork road. The data given in figure 1 are the corresponding two.

Solution: (1) As can be seen from Figure 2, it takes 0.8h for A to walk from A to D and 1.6km for walking, so the walking speed of A is = 1.60.8=2(km/h).

While A walked to C***, it took 1.8h and walked 2.6km.

So how long does A stay in D scenic spot = 1.8-0.8-2.6? 1.62= 1-0.5=0.5(h)，

So A stays at each scenic spot for 0.5h；;

A stayed at the scenic spot C for 0.5h, walked from 2.3h to 3h, and walked (3-2.3)×2= 1.4km, that is, * * * returned to A and walked 4km, drawing the right picture;

(2) From (1), A goes from C to A (3-2.3)×2= 1.4(km),

The distance from e to a is 0.8 kilometers.

So the distance between C and E is1.4-0.8 = 0.6 km;

(3) Their agreement can be realized for the following reasons:

The distance between c and e is 0.6 km,

∴ The distance to E-B-E-C is 0.4+0.4+0.6= 1.4 (km), and the distance to E-B-C is 0.4+ 1.3= 1.7 (km).

∴ The shortest tour route of B is: A→D→C→E→B→E→A (or A→E→B→E→C→D→A), and the total itinerary is1.6+/kloc-0.4× 2+0.8.

∴ The total time for B to return to A after three scenic spots =3×0.5+4.83=3. 1(h)

It took three hours,

∴ B is 0. 1 hour later than A, that is, it takes 6 minutes to reach A.

Their agreement can be fulfilled.