A unit organizes employee tours of four departments, stipulating that each department can only choose one in Shaoshan, Hengshan and Zhangjiajie, assuming that each department chooses.

Solution: The number of possible results when four departments of a certain unit choose three scenic spots is 3.4. Because they are randomly selected, the possibility of these results is equal.

(1) Choose two of the four departments as 1 group, and the other two departments as 1 group. There are ***3 groups, * * * each group has different scenic spots, and * * * has 3! Seed selection method,

∴ All three scenic spots have departments. What are the possible results?

Remember that "all three scenic spots have departmental choices" as the event A 1,

The probability of event A 1 is.

(2) Record "just two scenic spots have departments to choose" and "four departments all choose the same scenic spot" as events A 2 and A 3 respectively.

Then the probability of event A 3 is P(A 3 )=, and the probability of event A 2 is

P(a2)= 1-P(a 1)-P(a3)= .