The blanking budget and weight of the rebar worker

A, column main reinforcement

Foundation steel dowel = thickness of foundation slab-protective layer+length of steel bar extending into upper layer+maximum {10d, 200mm}

Second, the stirrup in the foundation

The stirrups in the foundation only play a stabilizing role, which can also be said to prevent the steel bars from being scratched when pouring. Generally, the calculation is based on 2 (the software uses 3 as the base).

Chapter II Intermediate Layer

A, column longitudinal reinforcement

1, KZ longitudinal reinforcement of middle layer = height-the height of the current layer protruding from the ground+the height of the previous layer protruding from the floor.

Second, the column stirrup

1, number of stirrups in KZ middle layer = n encrypted area/encrypted area spacing +N+ unencrypted area/unencrypted area spacing-1

03G 10 1- 1 central column stirrup encryption area is specified as follows.

1) The first column has three stirrup encryption zones, namely, the length of the lower stirrup encryption zone is HN/3; Max{500, column length dimension, HN/6} takes the upper part; Beam node range encryption; If the column is bound and overlapped, it needs to be encrypted within the overlapping range.

2) Stirrups of columns with more than one floor are respectively: the length of upper and lower stirrup encryption zone Max{500, and the length of column side HN/6 }；; Beam node range encryption; If the column is bound and overlapped, it needs to be encrypted within the overlapping range.

The third quarter penthouse

The top KZ is divided into corner column, side column and middle column due to different positions, so the top anchorage of longitudinal reinforcement of various columns is different. (See pages 37 and 38 of 03g 10 1- 1).

I. Corner column

Length of longitudinal reinforcement at the top of corner column = clear height HN+ anchorage value of reinforcement at the top, so how to consider anchorage value of reinforcement at the top of corner column?

Bending anchor (≦Lae): beam height-protective layer ++ 12d

A, the anchorage length of internal reinforcement is Lae: beam height-protective layer.

⊙ 1.5 lae

B, the anchorage length of the lateral reinforcement is the first floor at the top of the column: ⊙ beam height-protective layer+column width-protective layer +8d.

The second floor of the column top: ⊙ beam height-protective layer+column width-protective layer

Note: in GGJ V8. 1, the anchorage length of internal reinforcement is bending anchor (≦Lae): beam height-protective layer ++ 12d.

Straight anchor (Lae): beam height-protective layer

Transverse reinforcement anchorage length = max {1.5LAE, beam height-protective layer+column width-protective layer}

Second, the side column

Length of longitudinal reinforcement at the top of side column = clear height HN+ anchorage value of reinforcement at the top, so how to consider the anchorage value of reinforcement at the top of side column?

The anchorage of longitudinal reinforcement at the top of side column can be divided into internal reinforcement anchorage and external reinforcement anchorage:

A, the anchorage length of internal reinforcement is bending anchor (≦Lae): beam height-protective layer ++ 12d.

Straight anchor (Lae): beam height-protective layer

B, the anchorage length of the outer reinforcement ≧1.5lae.

Note: in GGJ V8. 1, the anchorage length of internal reinforcement is bending anchor (≦Lae): beam height-protective layer ++ 12d.

Straight anchor (Lae): beam height-protective layer

Transverse reinforcement anchorage length = max {1.5LAE, beam height-protective layer+column width-protective layer}

Third, the central column

Length of longitudinal reinforcement at the top of central column = clear height HN+ anchorage value of top reinforcement, so how to consider anchorage value of top reinforcement of central column?

The anchorage length of longitudinal reinforcement at the top of central column is bending anchor (≦Lae): beam height-protective layer ++ 12d.

Straight anchor (Lae): beam height-protective layer

Note: In GGJ version 8. 1, the processing is the same as above.

Chapter IV Board of Directors

In practical engineering, we know that slabs are divided into precast slabs and cast-in-place slabs. This paper mainly analyzes the reinforcement arrangement of cast-in-place slab.

Plate reinforcement mainly includes: stressed reinforcement (unidirectional or bidirectional, single-layer or double-layer), load-bearing negative reinforcement, distributed reinforcement, additional reinforcement (corner additional radial reinforcement, hole additional reinforcement) and lacing (double-layer reinforcement supports the upper and lower floors).

First, the stress bar

In the software, the length of the stress bar is calculated according to the shaft network.

Length of reinforced bar = axis size+left anchorage+right anchorage+hooks at both ends (if it is Grade I reinforcement).

Root number = (axis length-deduction number)/rebar spacing+1

Second, negative reinforcement and distribution reinforcement.

Negative reinforcement length = negative reinforcement length+left bend+right bend

Negative reinforcement quantity = (reinforcement range-deduction)/reinforcement spacing+1

Length of distributed reinforcement = length of negative reinforcement arrangement range-negative reinforcement minus impairment.

Negative reinforcement distribution quantity = negative reinforcement length in negative reinforcement input interface/distribution reinforcement spacing+1.

Three, additional reinforcement (corner additional radial reinforcement, hole additional reinforcement), support reinforcement (double steel support on the lower level)

According to the actual situation, the length and quantity of steel bars can be directly calculated, and the calculation can also be input in the software by direct input method.

Chapter V Frequently Asked Questions

Why do we calculate the hook of 135o as 1 1.9d in the software when calculating the reinforcement?

In the stirrup calculation in our software, the value of 1 1.9D is actually the result of hook plus measurement difference. We know that the straight length of the hook is 10D, so the measurement difference should be1.9d. Let's deduce the origin of the measurement difference of1.9d.:

The result calculated according to the outer skin is1000+300; If calculated according to the centerline, it is:1000-d/2-d+135/360 * 3.14 * (d/2+d/2) * 2+300, where d is the minimum radius specified in the specification, and the following is subtracted from the front.

How to deal with two kinds of hanging bars in the beam?

Connect two different booms with "/"in the boom information input box and put them into the boom input box, such as 2B22/2B25. The width of the back secondary beam is input in a one-to-one correspondence with the steel hanger, for example, 250/300(2B22 corresponds to 250 Liang Kuan; 2B25 corresponds to 300 Liang Kuan).

How to deal with the software when the steel bars on both sides of the middle support of the beam are different?

When the reinforcement on both sides of the middle bearing of the beam is different, we directly input the reinforcement that spans the negative reinforcement of the current right bearing and the negative reinforcement of the next left bearing in the software. The principle of software calculation is that the steel bars on both sides of the bearing are the same, and then pass; If not, anchor it; The principle of judgment is that if the input format is the same, it will pass, and if it is different, it will be anchored. If the negative reinforcement of the right bearing is 5B22 and the negative reinforcement of the next span left bearing is 5B22+2B20, then five 22 steel bars will pass through the bearing and two 20 steel bars will be anchored in the bearing.

How to deal with beam variable section in software.

In the software, variable cross-section beams can be divided into two types:

1, when the height difference >; 1/6 When the beam is high, whether the format on both sides is the same or not, the reinforcement on both sides shall be calculated as anchorage. The bending length is 15d ++ height difference.

2. When the height is poor

If the concrete strength grade of the frame column changes, how do we deal with the longitudinal reinforcement of the column?

If the concrete strength grade of the frame column changes, the longitudinal reinforcement of the column can be treated in two ways:

1, column longitudinal reinforcement adopts electroslag pressure welding, should be set according to the concrete strength grade at the top of the column;

2. If the longitudinal reinforcement of the column is bound and overlapped, for example, the 1 ~ 2 layer is C45, and the 3 ~ 10 layer is C35, then the column should be divided into two members: one is C45, which is 3 layers, but only the section size and height of the member are input in the third layer to avoid the second layer being used as the top calculation anchor; For another member, the 1 ~ 10 layer is established, and for the 1 ~ 2 layer, only the section size and height of the member are input, and the reinforcement information is input from the three layers, which can solve the problem.

The formula for calculating the length of cylindrical spiral reinforcement per meter is l = n(p * p+(d-2 b+do)2 *π2)0.5+ the length of two hooks.

Among them:

N= number of spiral turns, N=L/P(L is the length of the member, that is, the length of the cylinder).

P= pitch

D= member diameter

Do= diameter of spiral reinforcement

B= thickness of protective layer.

In addition:

Theoretical quality of reinforcement = calculated length of reinforcement * quality of reinforcement per meter.

Total consumption quality of steel bar = theoretical quality of steel bar *[ 1+ loss rate of steel bar (iron piece)]

Shortcut of theoretical quality calculation of reinforcement;

Theoretical mass of reinforcement = square of reinforcement diameter (unit: mm) * 0.005438+07.

Second, the conversion between CAD, word and excel.

First, the steps of copying CAD graphics or tables to WORD and EXCEL.

1. Change the value of the CAD system variable WMFBKGND to OFF to make the CAD background transparent.

If the graphic you want to copy is black and white, you can change the color of the layer to white (No.7) in the Layer Manager.

2. Select the graphics to copy and copy them with the copy tool;

3. Switch to WORD or EXCEL, activate the area to be pasted, and then select Edit-Paste;

4. Paste the initial effect as shown below;

5. Cut off the blank area of the graph by "image clipping", and then scale the graph to a suitable size by diagonal dragging;

6. The effect after cutting and scaling is shown in the figure below;

7. If the graphics need to be modified, you can return to CAD for modification, as shown in the figure below.

The method of copying to EXCEL is the same as above.

Second, copy WORD and EXCEL graphics or tables to CAD.

1. Select the graph or table to copy and use the copy tool to copy it;

2. Switch to CAD program, and then select Edit-Paste Special;

3. Choose to paste as AutoCAD primitive, so that you can edit it in CAD after pasting;

4. Select the paste insertion point, and the paste effect is shown in the figure below;

5. The pasted lines or words can be edited directly in CAD, as shown below;

Supplement from CAD to Office: This method can be used to paste CAD drawings into Word, Excel, PowerPoint and Publisher.

1, line width-it is recommended to set the line width with multi-segment lines, because there are only two widths after pasting, which is not beautiful;

2. Scale problem-if possible, try to draw with 1: 1, where 1: 1 is the printing scale, that is, it needs to be printed as 10mm.

Drawing into 10 graphic units can not only control the drawing scale, but also control the line width;

3. The background color -2002 can be copied in the layout space (the general layout space background is white), and 2004, 2005 and 2006 can be copied directly without modifying the background color.

3. What is the price of the construction contractor?

Template: 19-23 yuan /m2 (plastering surface)?

Specific: 38-4 1 yuan/Li,?

Reinforcement: 3 10-420 yuan/ton, or 10- 13 yuan /m2?

Masonry: 55-70 yuan/Li. ?

Plastering: 7- 15 yuan /m2 (excluding doors and windows and scaffolding)?

Brick paste 18/m2.

Indoor floor tile (600*600) 15 yuan /m2,

Kick line: 3 yuan/m,?

Indoor wall tiles: 25 yuan /m2 (including chamfering)?

Staircase stone: 28 yuan /m2, treadboard edging: 10 yuan /m?

Gypsum board ceiling: 20 yuan (flat shed) aluminum gusset plate hanging project: 25 yuan /m2,?

Partition of squatting platform: 120-300 yuan/rubbing position. ?

Dabai latex paint: 6 yuan /m2. ?

Exterior wall brick: 43 yuan /m2,?

Dry hanging mushroom stone on external wall: 50 yuan /m2. ?

Roof tile: 13 yuan/m2. ?

Water heating: 9 yuan /m2 (building area)?

Electrical lighting: 6 yuan/m2. ?

Woodworking: 18-24 yuan /m2 (plastering surface), woodworking 35-50 yuan /m2,?

5.5 yuan /m2, scaffolder?

Real estate construction cost (calculated in square meters)?

1, pile foundation engineering (if any): 70~ 100 yuan/m2; ?

2. Steel bar: 40~75KG/ m2 (low multi-layer content and high high-layer content), which is 160~300 yuan/m2; ?

3. Concrete: 0.3~0.5 m3/m2 (low multi-layer content and high high-layer content), totaling 100 ~ 165 yuan/m2; ?

4. Masonry works: 60~ 120 yuan /m2 (high multi-storey content and low high-rise content); ?

5. Plastering works: 25~40 yuan/m2; ?

6. Exterior wall engineering (including thermal insulation): 50~ 100 yuan/square meter (based on general paint, if it is stone or curtain wall, it may be as high as 300~ 1000 yuan/square meter; ?

7. Indoor water and electricity installation project (including fire protection): 60~ 120 yuan /m2 (according to the grade of the residential area, the multi-storey is slightly lower); ?

8. Roofing works: 15~30 yuan /m2 (high multi-layer content and low high-rise content); ?

9. Doors and windows engineering (excluding entrance doors): The building area is about 0.25~0.5 square meters per square meter (closely related to design and whether it is high-grade, with a large proportion of high-grade), and the cost is 90~300 yuan/square meter, generally 90~ 150 yuan/square meter. If you use high-grade aluminum alloy doors and windows, it may reach 300 yuan/square meter; ?

10, earthwork, porch, flue and public * * * decoration works: 30~ 150 yuan/square meter (this has a lot to do with the grade of the community, the higher the grade, the higher the cost); ?

1 1. Basement (if any): the cost is increased by 40~ 100 yuan /m2 (multi-storey content is higher and high-rise content is lower); ?

12. Elevator project (if any): 40~200 yuan /m2, which is closely related to elevator grade, elevator number and floor number. General project is about 100 yuan/m2; ?

13, labor cost: 130~200 yuan/m2; ?

14, outdoor supporting works: 30~300 yuan /m2, generally about 70~ 100 yuan /m2; ?

15, formwork, support and scaffolding works (cost): 70~ 150 yuan/m2; ?

16, tower cranes, people and goods elevators, lifts and other construction machinery (about 5~8% of the total cost: about 60~90 yuan/m2; ?

17. Temporary facilities (site temporary facilities such as living quarters, office areas, warehouses and roads (production rooms such as water, electricity, sewage, video and production sheds): 30~50 yuan/m2; ?

18, inspection, test, formalities, transportation, communication and other expenses: 10~30 yuan/m2; ?

19, contractor's management fee, data, labor insurance, profit and other expenses (about 10%) * 10%=90~ 180 yuan/m2; ?

20. Pay various national taxes and fees (3.3 ~ 3.5% of the total cost): 33 ~ 70 yuan/square meter, and high-grade products may be as high as 100 yuan/square meter. ?

Not counting fine decoration, the general cost is about1000 ~ 2,000 yuan/square meter, and the high-grade residential area can reach more than 3,500 yuan. The above does not include the cost of corruption brought about by the development of some state-owned enterprises. Fine decoration costs are generally 500~ 1500 yuan/square meter, depending on the level. There is also a simple decoration in 300 yuan/square meter, or even an ultra-high-grade decoration (carrying a bag) of 3000~ 10000 yuan/square meter. ?

2 1. Design fee (including the fee for the preliminary design concept period): 15~ 100 Yuan/m2; ?

22. Supervision fee: 3~30 yuan/m2; ?

23. Agency fees for advertising, planning and sales: generally 30~200 yuan /m2, and the highest can reach more than 500 yuan /m2; ?

24. Land cost: generally, the urban area of second-tier cities (old suburbs) is 70- 1 10,000/mu, and the plot ratio is generally 1.0-2.0, so the converted house price is: 525- 1500 yuan/square meter, and the urban area is generally 2 million yuan/mu. The converted house price is: The unilateral cost of land in third-tier cities and counties is relatively low, generally 100~500 yuan/square meter, and some are as high as 2000 yuan/square meter or more; ?

25. Land taxes and upfront fees are generally about 15% of land costs, while in second-tier cities, they are generally 100 ~ 500 yuan /m2, and the standards vary from place to place. ?

Conclusion: The capital construction cost is fixed. Even if the relocation house is built according to the national minimum standard, the cost is hardly lower than 1 1,000 yuan/square meter. In fact, the construction and installation cost of multi-storey ordinary commercial housing is about 1200 yuan/m2, and that of small and high-rise ordinary commercial housing is about 1500~ 1800 yuan/m2. The higher the grade, the higher the cost. The main benefits are: the grade of the community, land fees paid to the government and local government taxes and fees, advertising planning and sales costs, decoration costs and so on. In addition, the developer's development quality also has a certain relationship. If the price is kept down, the quality will be worse. The cost of private developers is indeed lower than that of state-owned/government developers, mainly for two reasons. First, most private enterprises focus on efficiency, and their costs are generally well controlled. Second, the corruption cost of private enterprises is relatively lower. Whatever the reason, the cost of the same quality community will not exceed 100~200 yuan /m2. ?

Public basic knowledge

A square wall of 12 needs 64 standard bricks.

A square wall of 18 needs 96 standard bricks.

A square with 24 walls needs 128 standard bricks.

A square with 37 walls needs 192 standard bricks.

A square with 49 walls needs 256 standard bricks.

Calculation formula:

The consumption of 240 wall tiles per cubic meter is 1/(0.24*0. 12*0.6).

The consumption of 370 wall tiles per cubic meter is 1/(0.37*0. 12*0.6).

A square hollow 24 wall needs more than 80 standard bricks.

Information that civil engineers should master (turn)

A, ordinary residential building concrete consumption and steel consumption:

1, multi-storey masonry residence:

Reinforcement 30KG/m2

Concrete 0.3-0.33 m3/m2

2. Multilayer framework

Steel bar 38-42kg/m2

0.33-0.35 m3/m2 of concrete

3. Small high-rise building 1 1- 12 floor

Reinforcement 50-52kg/m2

Concrete 0.35 m3/m2

4. High-rise 17- 18 Floor

Steel bar 54-60kg/m2

Concrete 0.36 m3/m2

5. Top 30 H=94 m

Steel bar 65-75 kg/m2

0.42-0.47 m3/m2 of concrete

6. The 28th floor of high-rise serviced apartment is H=90 meters.

Steel bar 65-70kg/m2

0.38-0.42 m3/m2 of concrete

7. The amount of concrete and steel used in the villa is between the multi-storey masonry residence and the high-rise11-12 floors.

The above data are designed according to the rule of earthquake 7 degree zone.

Second, the ordinary multi-storey residential building construction budget economic indicators

1. Outdoor doors and windows (excluding unit doors and security doors) account for 0.20-0.24 of the construction area.

2. The formwork area accounts for about 2.2% of the building area.

3. The outdoor plastering area accounts for about 0.4 of the building area.

4. Indoor plastering area accounts for 3.8% of the building area.

Third, the construction effect

1, the daily plastering capacity of a Plaster workers is 35 square meters.

2. A bricklayer lays 1000- 1800 red bricks a day.

3. A bricklayer lays 800- 1000 hollow bricks a day.

4. Tiles15m2

5. The first scraping is 300 m2/ day, the second scraping is 180 m2/ day, and the third scraping is 90 m2/ day.

Fourth, the basic data

1, concrete weight 2500KG/m3.

2. The reinforcement weight per linear meter is 0.00617 * d * d * d.

3, dry sand weight 1500KG/m3, wet sand weight 1700KG/m3.

4. The stone weight is 2200KG/m3.

5. About 525 red bricks per cubic meter (wall thickness)

6. One cubic meter of hollow brick is about 175.

7. Screen side cleaning sand requires 1.3 cubic meters of ordinary sand.

A little different view:

1. General multi-storey masonry residence: steel bar 25-30KG/m2, of which affordable housing 16- 18kg/m2.

2. For general multi-storey masonry houses, the outdoor plastering area accounts for 0.5-0.7 of the construction area.

3. Generally, the formwork area accounts for 1.3-2.2 of the building area, which varies greatly according to the number of cast-in-place slabs and the density of columns.

4. A bricklayer builds 240 brick walls a day1000-1800,370 or 500 walls 2000-3000.

5. The weight of reinforced concrete is 2200KG/m3, and that of plain concrete is 2 100KG/m3.

6. The weight of engineering stone is 1800KG/m3. )

0.6 17 is the reinforcement weight per meter of circle 10. The weight of steel bars is proportional to the square of the diameter (radius).

G=0.6 17*D*D/ 100

Weight per meter (kg) = rebar diameter (mm)× rebar diameter (mm)×0.006 17.

In fact, the weight of steel bars commonly used in construction projects is also very simple: φ 6 = 0.222kgφ 6.5 = 0.26kgφ 8 = 0.395kgφ10 = 0.617 kgφ12 = 0.888kgφ14 =/kloc. 18 = 2.0kg φ 24 = 2.47kg φ 22 = 2.98kg φ 25 = 3.85kg φ 28 = 4.837kg. ............

Steel bars below φ 12 (including 12) and φ 28 (including 28) generally take three decimal places, and steel bars from φ 14 to φ 25 generally take two decimal places.

φ 6 = 0.222kg.

φ8 = 0.395kg

φ 10 = 0.6 17kg

φ12 = 0.888kg.

φ 14 = 1.2 1kg

φ 16 = 1.58kg

φ 18 = 2kg

φ 20 = 2.47kg.

22 = 3Kg

φ 25 = 3.86kg.

I have an empirical formula. Just calculate your own table. You can also buy a book with a watch, which is also very convenient to use.

A simple formula for calculating the theoretical weight of steel

Material Name Theoretical Weight W (kg/m)

Flat steel, steel plate and steel strip w = 0.00785× width× thickness

Square steel w = 0.00785× side length 2

Round steel, steel wire and steel wire w = 0.006 17× diameter 2.

Steel pipe w = 0.02466× wall thickness (outside diameter-wall thickness)

Equiangular W = 0.00785× side thickness (2 side width-side thickness)

Unequal angle steel w = 0.00785× side thickness (long side width+short side width-side thickness)

I-beam w = 0.00785× waist thickness [height +f (leg width-waist thickness)]

Channel steel w = 0.00785× waist thickness [height +e (leg width-waist thickness)]

comment

The exact calculation formulas of 1, angle steel, I-beam and channel steel are very complicated, so the approximate values are calculated by table simplification.

2.f value: 3.34 for general model and A model, 2.65 for B model and 2.26 for C model. ..

3.e value: 3.26 for general model and A model, 2.44 for B model and 2.24 for C model. ..

4. All length units are millimeters.

A, ordinary residential building concrete consumption and steel consumption:

1, multi-storey masonry residence:

Reinforcement 30KG/m2

Concrete 0.3-0.33 m3/m2

2. Multilayer framework

Steel bar 38-42kg/m2

0.33-0.35 m3/m2 of concrete

3. Small high-rise building 1 1- 12 floor

Reinforcement 50-52kg/m2

Concrete 0.35 m3/m2

4. High-rise 17- 18 Floor

Steel bar 54-60kg/m2

Concrete 0.36 m3/m2

5. Top 30 H=94 m

Steel bar 65-75 kg/m2

0.42-0.47 m3/m2 of concrete

6. The 28th floor of high-rise serviced apartment is H=90 meters.

Steel bar 65-70kg/m2

0.38-0.42 m3/m2 of concrete

7. The amount of concrete and steel used in the villa is between the multi-storey masonry residence and the high-rise11-12 floors.

The above data are designed according to the rule of earthquake 7 degree zone.

Second, the ordinary multi-storey residential building construction budget economic indicators

1. Outdoor doors and windows (excluding unit doors and security doors) account for 0.20-0.24 of the construction area.

2. The formwork area accounts for about 2.2% of the building area.

3. The outdoor plastering area accounts for about 0.4 of the building area.

4. Indoor plastering area accounts for 3.8% of the building area.

Third, the construction effect

1, the daily plastering capacity of a Plaster workers is 35 square meters.

2. A bricklayer lays 1000- 1800 red bricks a day.

3. A bricklayer lays 800- 1000 hollow bricks a day.

4. Tiles15m2

5. The first scraping is 300 m2/ day, the second scraping is 180 m2/ day, and the third scraping is 90 m2/ day.

Fourth, the basic data

1, concrete weight 2500KG/m3.

2. The reinforcement weight per linear meter is 0.00617 * d * d * d.

3, dry sand weight 1500KG/m3, wet sand weight 1700KG/m3.

4. The stone weight is 2200KG/m3.

5. About 525 red bricks per cubic meter (wall thickness)

6. One cubic meter of hollow brick is about 175.

7. Screen side cleaning sand requires 1.3 cubic meters of ordinary sand.

Some calculation formulas of decoration

1, floor tile consumption: (note that the loss rate of different rooms is generally about 1-5%)

Dosage per 100 m = 100/[ (block length+mortar joint width) × (block width+mortar joint width) ]×( 1+ loss rate)

For example, the specification of retro floor tile is 0.5×0.5M, the flat-fell seam width is 0.002M, the loss rate is 1%, and the number of blocks required for 100 m2 is:

100 m2 dosage =100/[(0.5+0.002) × (1.01) is about 40 1.

Total price of floor tiles = number of floor tiles × unit price of floor tiles

2. Upper limit dosage:

Ceiling consumption = (length-shielding length) × (width-shielding width)

For example, the number of PVC plastic ceilings is calculated according to the net size area. The unit price of PVC plastic board is 50.8 1 yuan per square meter, the shielding length and width are 0.24m, the ceiling length is 3m, and the width is 4.5m. The dosage is as follows:

The dosage of ceiling board = (3-0.24) × (4.5-0.24) is approximately equal to 1 1.76 per square meter.

3, door dosage:

Amount of door covering material = door frame length × door frame width

For example, the door (as shown in the figure) is wrapped with composite board, and the outer frame of the door is 2.7M long and 1.5M wide. Material consumption is as follows:

The amount of door covering material =2.7× 1.5=4.05 square meters.

4, wallpaper dosage:

Use of wallpaper = (height-shielding length) × (width-shielding width )× number of walls-door area-window area.

For example (as shown in the figure), if the wall is shaded by 24CM, the wall is 2.5M high and 5M wide, the door area is 2.8 square meters, and the window area is 3.6 square meters, then the dosage is as follows:

The amount of wallpaper = [(2.5-0.24) × (5-0.24) ]× 4-2.8-3.6 is about 36.6 square meters.

The above is the calculation of partial material consumption. The total material cost of decoration engineering is obtained by multiplying the material consumption of each part with their respective unit prices and accumulating them.

5. Floor dosage: (solid wood)

Longitudinal dosage = room length/floor tile length

Horizontal dosage = room width/floor tile width

In case of infinite division, carry method should be adopted, which cannot be rounded, but a block smaller than half in the vertical direction is regarded as a block, and a block larger than half is regarded as a block.

Total floor price = total consumption × unit price

Floor loss = floor area-house area

Floor loss rate = floor loss/housing area

Note: The general floor loss rate does not exceed 5%.

6, the amount of wall materials

After determining the color and variety of the wall materials, we can reasonably calculate the size of the materials according to the size of the living room. Considering the possible loss in the construction process, you can buy about 5% more than the actual consumption. There are two methods to calculate wall materials:

1. Calculated by the formula, it is the area of the room multiplied by 2.5, and the product is the amount of materials used for sticking to the wall. For example, a room of 20 square meters is made of 20×2.5=50m. There is a more accurate formula:

S=(L/M + 1)(H + h) + C/M

Where: s—— the length (m) of the required wall sticking material.

L- Total length of four walls after deducting doors and windows (m)

M—— the width of the wall material (m), plus 1 as the allowance of the mosaic pattern;

H- the height of the required wall materials (m)

H—— the distance (m) between two identical patterns on the wall sticking material.

C- Area of upper and lower walls such as windows and doors (m2)

2. Field measurement shows that this method is more accurate. First, understand the width of the wall material to be selected and measure the perimeter of the room wall (excluding doors, windows, etc.). ) according to this width. There are several widths of wall materials around, but several pieces need to be pasted. Then measure the height of the wall to be pasted and multiply it by the number of frames, that is, the length (m) of the wall pasting material required for some walls except doors and windows. Finally, this method is used to measure the length of the required material under the window wall and at the irregular corner, and the calculated length is the total length. This method is more suitable for fine-grained patterns, and there is no need for special alignment wall materials when splicing.

7, coating dosage estimation method

Introduce a simple calculation method:

The room area (square meters) is divided by 4, and the height (decimeter) of the wall to be painted is divided by 4. The sum of these two figures is the kilograms of paint needed. For example, a room with an area of 20 square meters and a wall height of 16 decimeter (except for the dado of 12 decimeter) is (20÷4)+( 16÷4)=9, that is, 9 kilograms of paint can be used to paint the wall twice.

It's all there.